Optional utility type in TypeScript

I was scaling a TypeScript definition and get to know this beautiful TypeScript feature.

Hello
I'm Vikash Kumar.

TypeScript has Omit<> | Pick<> | Partial<>

That do almost all the work I need mostly playing with Type definitions, but somewhere they are lacking behind to fulfil my desires.

Suppose, I want to make some of fields in my type definition optional.

Like this

type Config = {
  name: string;
  version: string;
  description: string;
};

type PartialConfig = {
  name: string;
  version: string;
  description?: string;
}; 

I am not going to write down always as:

type PartialConfig = Omit<Config, 'description'> & Partial<Pick<Config, 'description>>

So what I did instead:

export type Optional<T, K extends keyof T> =
  Omit<T, K> & Partial<Pick<T, K>>;

Now:

type Config = {
  name: string;
  version: string;
  description: string;
};

type PartialConfig = Optional<Config, 'description'>

Really, That simple now this Optional<> generic can be used anywhere in the codebase.

Thanks for Reading!